Question

a parent swings a 18.5 kg child in a circle of radius 1.05m, making 5 revolutions in 13.4s. what centripetal acceleration does the child experience?(unit=m/s^2)

Answer 1

5.77

Step-by-step explanation:

The answer is 5.77 on acellus.

Answer 2

Answer:
`0.146 m/s^(2)`

Step-by-step explanation:

The centripetal acceleration
`a_(c)` of an object moving in a uniform circular path is given by the following equation:

`a_(c)=(V^(2))/(r)` (1)

Where:

`V` is the tangential velocity

`r=1.05 m` is the radius of the circle

On the other hand, the tangential velocity is expressed as:

`V=\omega r` (2)

Where
`\omega` is the angular velocity, which can be found knowing the child makes 5 revolutions in 13.4s:

`\omega=(5 rev)/(13.4 s)=0.37 rev/s` (3)

Substituting (3) in (2):

`V=(0.37 rev/s)(1.05 m)` (4)

`V=0.39 m/s` (5)

Substituting (5) in (1):

`a_(c)=((0.39 m/s)^(2))/(1.05 m)` (6)

Finally:

`a_(c)=0.146 m/s^(2)`