Question

2. The water is then heated to its boiling point. Calculate the specific latent heat of

vaporisation if there was 330 g of water before the loo was added, and 813,600 J of
energy is supplied to boil all of the water once it has reached its boiling point.
Answer:

Answer 1

2465 J/g

Step-by-step explanation:

The amount of energy required to boil a sample of water already at boiling point is given by

`Q=m\lambda_v`

where

m is the mass of the water sample

`\lambda_v` is the specific latent heat of vaporization of water

In this problem, we know

`Q=813,600 J`

`m = 330 g`

Solving the equation for
`\lambda_v`, we find

`\lambda_v = (Q)/(m)=(813600)/(330)=2465 J/g`