what is the acceleration of the 698 kg car that experiences a force of 2410 N ?
Answer:
![a = 3.45 m/s^2](https://img.qammunity.org/2020/formulas/physics/middle-school/ffv9navsdan5k2xcvvrg18u9pjwnsse7rg.png)
Step-by-step explanation:
Here we know that
F = 2410 N
m = 698 kg
now we will have
![F = ma](https://img.qammunity.org/2020/formulas/physics/high-school/6dslirwz7efajuroewtnbxamr1m7rpia2b.png)
![2410 = 698 a](https://img.qammunity.org/2020/formulas/physics/middle-school/xaus46py7aolnryeu846dwqakekb3fc82j.png)
![a = (2410)/(698)](https://img.qammunity.org/2020/formulas/physics/middle-school/ntn1guqxv8nnbq0mo9345urtvuhgwjuzeq.png)
![a = 3.45 m/s^2](https://img.qammunity.org/2020/formulas/physics/middle-school/ffv9navsdan5k2xcvvrg18u9pjwnsse7rg.png)
what is the force required to propel a 2.00 kg object at a rate of 2.71 x 10^5 m/s^2 ?
Answer:
![F = 5.42 * 10^5 N](https://img.qammunity.org/2020/formulas/physics/middle-school/iz7bwy3ags5bh5ykhsw0cq90li7p4g67u8.png)
Step-by-step explanation:
Mass = 2 kg
![acceleration = 2.71 * 10^5 m/s^2](https://img.qammunity.org/2020/formulas/physics/middle-school/fkxw0hbmxybs04c9va0qrr7v9drhklm70k.png)
now we know that
![F = ma](https://img.qammunity.org/2020/formulas/physics/high-school/6dslirwz7efajuroewtnbxamr1m7rpia2b.png)
![F = 2(2.71 * 10^5)](https://img.qammunity.org/2020/formulas/physics/middle-school/141uro0g0p22un4kqyfwq6cpci7amvx15i.png)
![F = 5.42 * 10^5 N](https://img.qammunity.org/2020/formulas/physics/middle-school/iz7bwy3ags5bh5ykhsw0cq90li7p4g67u8.png)