Question

In the two-slit experiment, monochromatic light of frequency 5.00 × 1014 Hz passes through a pair of slits separated by 2.20 × 10-5 m. (c = 3.00 × 108 m/s) (a) At what angle away from the central bright spot does the third bright fringe past the central bright spot occur?

Answer 1

`\theta=4.64^(\circ)`

Step-by-step explanation:

It is given that,

The frequency of monochromatic light,
`f=5* 10^(14)\ Hz`

Slit separation,
`d=2.2* 10^(-5)\ m`

Let
`\theta` is the angle away from the central bright spot the third bright fringe past the central bright spot occur. The condition for bright fringe is :

`d\ sin\theta=n\lambda`

n = 3

`\lambda=(c)/(f)`

`d\ sin\theta=(nc)/(f)`

`sin\theta=(nc)/(fd)`

`sin\theta=(3* 3* 10^8)/(5* 10^(14)* 2.2* 10^(-5))`

`\theta=4.64^(\circ)`

So, at 4.64 degrees the third bright fringe past the central bright spot occur. Hence, this is the required solution.