Answer:
The probability of failure of both radios is 0.00003364.
The flight becomes much safer with two independent radios
Explanation:
When you have two events A and P with probabilities P(A)=q and P(B)=r, if the events are independent (that is to say, if the occurrence of one event does not influence the occurrence of the other), then
where the event intersection means the probability of the occurrence of both events.
If we call P(A) the probability of a radio failure, as the occurrence of failure of a radio is independent of having another radio, then the probability of the failure of both radios is
(0.0058)*(0.0058) = 0.00003364
So, the probability that a particular flight will be threatened with the failure of both radios is 0.00003364.
Hence the flight becomes much safer with two independent radios