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1 vote
Find the first three iterates of the function f(z) = 2z + (3 - 2i) with an initial value of

z0 = 1 + 2i.
a.
5 + 2i, 13 + 2i, 29 + 2i
c.
5 - 2i, 13 - 2i, 29 - 2i
b.
3 + 2i, 17 + 2i, 23 + 2i
d.
3 - 2i, 17 - 2i, 23 - 2i


Please select the best answer from the choices provided

User Biff
by
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1 Answer

4 votes

Answer:

D

Explanation:

The options differ in the 1st iteration, so you only need to calculate f(z0) = 2*4+(3-2i) = 11-2i. --> D

User Nasia Jaffri
by
5.0k points