Answer:
The answer to your question is: 12 ml of HCl
Step-by-step explanation:
Data
Na2CO3 V = 30 ml [ ] = 0.1 mol/l
HCl = 0.5 mol /L V = ?
Balance reaction
Na₂CO₃ + 2HCl ⇒ 2NaCl + CO₂ + H₂O
Process
1.- Find the number of moles of Na2CO3
Molarity = n / V
n = VM n = (30)(0.1) = 3 moles
2.- From the reaction
1 mol of Na2CO3 --------------- 2 HCl
3 mol ------------------------------- x
x = (3 x 2) / 1
x = 6 moles of HCl
3.- Volume of HCl
V = n / M V = 6 / 0.5
V = 12 ml