Answer:
The theoretical mass of BaSO4 is 4.847g
Step-by-step explanation:
Step 1: The balanced equation
MgSO4(aq) + Ba(NO3)2(aq) → Mg(NO3)2(aq) + BaSO4(s)
Step 2: Given data
mass of MgSO4 = 2.5grams
Molar mass of MgSO4 = 120.366 g/mole (periodic table)
Step 3: Calculate number of moles MgSO4
moles of MgSO4 = mass of MgSO4 / Molar Mass of MgSO4
moles of MgSO4 = 2.5g / 120.366g /mole
moles of MgSO4 = 0.02077 moles
Step 4: Calculate moles of BaSO4
We can see in the balanced equation that for 1 mole of MgSO4 consumed, there is 1 mole of Ba(NO3)2 consumed and 1 mole of Mg(NO3)2 and 1 mole of BaSO4 produced.
This means that for 0.02077 moles MgSO4 consumed, there is 0.02077 moles of BaSO4 produced.
Step 5: Calculate mass of BaSO4
mass of BaSO4 = moles of BaSO4 * Molar mass of BaSO4
mass of BaSO4 = 0.02077 moles * 233.38 g/mole
mass of BaSO4 = 4.847g
The theoretical mass of BaSO4 is 4.847g