Question

3.0 mol of gas occupy 33.6 L at a temperature of 0°C. What is the pressure of the gas?

Answer 1

-2.02

Step-by-step explanation:

By firmula pv=nRT

Answer 2

The pressure of the gas is P=1.99 atm

Step-by-step explanation:

Given:

Amount of gas substance, n=3.0 mol

Volume of the gaseus substance V=33.6 L

To find :

Pressure of the gas =?

Solution:

According to Ideal gas Law,

`P V=n R T`

Where

p = pressure of the gas,

V = volume of the gas

n = amount of substance

R = ideal gas constant

T = temperature of the gas

Re-arranging the formula we get,

`P V=n R T`

Substituting the values ,

`P=\frac{3 * 0.082 \mathrm{Latm} \mathrm{mol}^(-1) \mathrm{K}^(-1) * 273.25 \mathrm{K}}{33.6 \mathrm{Lmol}^(-1)}`

`P=\frac{3 * 0.082 \mathrm{Latm} \mathrm{mol}^(-1) \mathrm{K}^(-1) * 273.25 \mathrm{K}}{33.64 \mathrm{mol}^(-1)}`

`P=\frac{3 * 0.082 \mathrm{atm} * 273.25}{33.6}`

`P=(67.19 a t m)/(33.6)`

`P=1.99 \mathrm{atm}`

Result :

The pressure of the gas is P=1.99 atm.