Question

A flask containing 855 grams of water was heated. If the temperature of the water was raised from 21.0 to 85.0 degrees Celsius, how much heat (in joules) did the water absorb? the specific heat capacity of liquid water is 4.184J/g per C

Answer 1

The heat absorbed by the water is 228,948.48 J

Step-by-step explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

In this way, between heat and temperature there is a direct proportional relationship (Two magnitudes are directly proportional when there is a constant so that when one of the magnitudes increases, the other also decreases; and the same happens when either of the two decreases .). The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat and the mass of the body. So, the equation that allows to calculate heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature.

In this case:

• c= 4.184
  `(J)/(g*C)`
• m=855 g
• ΔT= Tfinal - Tinitial= 85 °C - 21°C= 64 °C

Replacing:

Q= 4.184
`(J)/(g*C)` *855 g* 64 C

Solving:

Q= 228,948.48 J

The heat absorbed by the water is 228,948.48 J