Answer and explanation:
Statement - If the difference of two numbers is even then so is their sum.
Let the two even numbers be '2m' and '2n' with m and n are integers.
The difference of two number is
![2m-2n=2(m-n)](https://img.qammunity.org/2020/formulas/mathematics/college/8xov145hlgz682fcl96u6cniqr9ae5wjza.png)
Now, The sum of the numbers is
![2m+2n=2(m+n)](https://img.qammunity.org/2020/formulas/mathematics/college/pprlg8hd7gxh6curtn4hz1b3ih8x37osex.png)
Let
where k is an integer
Then,
which is also an even number as 2 is multiplied with it.
So, If the difference of two numbers is even then so is their sum.
For example -
Let two even number 2 and 4.
The difference is
, 2 is even.
The sum is
, 6 is even.