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On the first math test, Keiko answered 19 out of 25 questions correctly. On the

second test she got 17 out of 20 correct. On which test did she get a better grade? Can you compare these two ratios as they are written? Explain why or why not.

User Norwebian
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1 Answer

4 votes

Answer:

Keiko got a better answer on the test on her second test, and you could compare these two ratios as they are written.

Explanation:

First: Convert each of the scores into percentages:

How do you convert ratios to percentages? Well, first we have to convert the ratio to a decimal or a fraction. Let's convert it to a fraction. So, 19 out of 25 will become
(19)/(25), and 17 out of 20 will become
(17)/(20). To convert a fraction to a percentage:

  • Divide the numerator by the denominator:

19 ÷ 25 = 0.76 AND 17 ÷ 20 = 0.85

  • Multiply your quotient by 100

0.76 x 100 = 76 AND 0.85 x 100 = 85

  • Add the percent sign

76% AND 85%

Now the two quantities are easier to compare. We can obviously see that 85% is bigger [and better] than 76%. So, the ratio that equals 85% - 17 out of 20 - is a better grade.

The second question was: Can you compare these two ratios as they are written? Explain why or why not.

Yes, you can compare these two ratios, just find the [positive] difference between the amount that she scored and the total number of scores that could be gained.

25 - 19 = 6

20 - 17 = 3

Since the equation with 20 and 17 in it has a smaller difference, it is most likely to have a greater value [because that means that Keiko got more right and less wrong, which means a greater mark which is also a greater quantity].

Thanks,

Topic: Quantity Relationships, Quantity Conversions

User PopKernel
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