Answer:
When n is gamma:
Also known as the heat capacity ratio.
Step-by-step explanation:
For an ideal gas of constant heat capacity, if we want an adiabatic process, that is, a process in which there is no entropy change, we will have the following relation:
![dU = T dS - Pd V\\dS= 0 \implies dU= -PdV](https://img.qammunity.org/2020/formulas/engineering/college/ir93j3v0kgqp68l20ogsr6hrgor9bx1czt.png)
But we also know that
![dU = C_v dT](https://img.qammunity.org/2020/formulas/engineering/college/ndon28sim7iecfl0jawc87osc64soa51b8.png)
Moreover, we have by the ideal gas law:
![PV= NR\, T\\VdP + PdV = NR \, dT](https://img.qammunity.org/2020/formulas/engineering/college/iflh0gi09fk8hbpqowq2ezd6l47i78bih1.png)
Now, if we eliminate dT from the last equations, we get:
![VdP + P dV = NR\, \Big( -\cfrac{P dV}{C_v}\Big)](https://img.qammunity.org/2020/formulas/engineering/college/fudt5w4lhmxxn2invwiuzyf3fwbdgpmuu8.png)
If we act algebraically on this, we get:
![\Big( 1 + \cfrac{NR}{C_v} \Big) \cfrac{dV}{V}+ \cfrac{dP}{P}=0](https://img.qammunity.org/2020/formulas/engineering/college/wtf5yj6nnhsni9xm8qed8092hoarjdmu1b.png)
Now, the coeffcient on the left :
![1 + \cfrac{NR}{C_v} = \cfrac{C_v+NR}{C_v } = \cfrac{C_p}{C_v} = \gamma](https://img.qammunity.org/2020/formulas/engineering/college/iwqaq2cd9ja0nbxi64npgcfcz4ds102tqb.png)
Where we have made use of so called Mayer's relation for an ideal gas:
![C_p= C_v + NR](https://img.qammunity.org/2020/formulas/engineering/college/ga7bd8t5360flrwylqsxsthqybo9rfmd8c.png)
Going back to our last equation, we find:
![\gamma \cfrac{dV}{V}+ \cfrac{dP}{P}=0\\](https://img.qammunity.org/2020/formulas/engineering/college/hp3p3fnbfkbphqv6zpzme5jyrsaxv57onb.png)
We can integrate this and get:
![\gamma \ln V + \ln P = K\\\ln (P\, V ^\gamma ) = K\\\\PV^\gamma = C](https://img.qammunity.org/2020/formulas/engineering/college/hr7xez8om630h4pdag4a4pt0zphnkvgxld.png)
Where K and C are just integration constants.