Question

A hollow steel cylinder with an outside diameter of 100 mm is required to carry a tensile load of 500 kN. Given that the allowable stress is limited to 120 MPa, determine the maximum inside diameter of the tube.

Answer 1

Maximum inside diameter is 68.52 mm.

Step-by-step explanation:

Apply stress formula to calculate inside diameter of the tube. Take the allowable stress for safe design and maximum inside diameter of the steel tube.

Step1

Given:

Outside diameter is 100 mm.

Tensile load is 500 kN.

Allowable stress is 120 Mpa.

Calculation:

Step2

Inside diameter is calculated by the stress formula as follows:

`\sigma_(a)=(F)/(A)`

`\sigma_(a)=(F)/((\pi)/(4)(d_(o)^(2)-d_(i)^(2)))`

`120=(500*1000)/((\pi)/(4)(100^(2)-d_(i)^(2)))`

`(100^(2)-d_(i)^(2))=5305.164`

`d_(i)=68.52`mm

Thus, the inner diameter is 68.52 mm.