Question

Approximate the field by treating the disk as a +6.7 μ C point charge at a distance of 48 cm.

Answer 1

`E = 2.62 * 10^5 N/C`

Step-by-step explanation:

Electric field due to a point charge is given as

`E = (kq)/(r^2)`

here we know that

`q = 6.7 \mu C`

`r = 48 cm`

now plug in all values in it

`E = ((9* 10^9)(6.7\mu C))/(0.48^2)`

`E = 2.62 * 10^5 N/C`

so here electric field is given due to point charge as above