Question

A car moving in a straight line starts at x = 0 at t = 0. It passes the point x = 25.0 m with a speed of 11.0 m/s at t = 3.00 s. It passes the point x = 385 m with a speed of 45.0 m/s at t = 20.0 s. Find (a) the average velocity, and (b) the average acceleration, between t = 3.00 s and t = 20.0 s.

Answer 1

a) V = 21.18m/s

b) a = 2m/s^2

Step-by-step explanation:

To calculate average velocity we will use the known positions of the car:

`V=\frac{X_(20)-X{3}}{\Delta t}`

Replacing the values:

`V=(385-25)/(20-3)=21.18m/s`

For the acceleration, we will use the given velocities:

`a=\frac{V_(20)-V{3}}{\Delta t}`

Replacing the values:

`V=(45-11)/(20-3)=2m/s^2`