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Four springs with the following spring constants, 113.0 N/m, 65.0 N/m, 102.0 N/m, and 101.0 N/m are connected in series. What is their effective spring constant? 004393 Submit Answer Incorrect. Tries 4/99 Previous Tres If a mass of 0.31 kg is attached what will be the frequency of oscillation?

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Answer:


K_e_q=22.75878093(N)/(m)


f=1.363684118Hz

Step-by-step explanation:

In order to calculate the equivalent spring constant we need to use the next formula:


(1)/(K_e_q) =(1)/(K_1) +(1)/(K_2) +(1)/(K_3) +(1)/(K_4)

Replacing the data provided:


(1)/(K_e_q) =(1)/(113) +(1)/(65) +(1)/(102) +(1)/(101)


K_e_q=22.75878093(N)/(m)

Finally, to calculate the frequency of oscillation we use this:


f=(1)/(2(pi)) \sqrt{(k)/(m) }

Replacing m and k:


f=(1)/(2(pi)) \sqrt{(22.75878093)/(0.31) } =1.363684118Hz

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