Question

Ii) (1 + x) y dx + ( 1 +y ) x dy = 0.​

Answer 1

Explanation:

`(1 + x)ydx + (1 + y)xdy = 0`

`(1 + y)xdy = -(1 + x)ydx`

`dy = (-(1 + x)ydx)/((1 + y)x)`

`(dy)/(dx) = (-(1 + x)y)/((1 + y)x)`