Question

What is the amount of heat, in Sl units, necessary to melt 1 lb of ice?

Answer 1

Heat required to melt 1 lb of ice is 151.469 KJ

Step-by-step explanation:

We have given mass of ice = 1 lb

We know that 1 lb = 0.4535 kg

Latent heat of fusion for ice =334 KJ/kg

Amount if heat for fusion of ice is given by

`Q=mL`, here m is mass of ice and L is latent heat of fusion

So heat
`Q=mL=0.4535* 334=151.469kj`

So heat required to melt 1 lb of ice is equal to 151.469 KJ