Question

A 1500 kg vehicle is moving on a dry pavement where the coefficient of friction is 0.80. If the vehicle is traveling at 25 m/s, what minimum distance is required to stop it when the brakes are applied. a. 40 m

b. 55 m
c. 72 m
d. 64 m

Answer 1

The minimum distance is 40 m.

(a) is correct option.

Step-by-step explanation:

Given that,

Mass of vehicle = 1500 kg

Coefficient friction = 0.80

Speed = 25 m/s

We need to calculate the acceleration

Using frictional force

`f=\mu mg`

Put the value into the formula

`ma=\mu mg`

`a = \mu g`

We need to calculate the distance

Using equation of motion

`v^2=u^2+2as`

Put the value into the formula

`0=25^2-2times\mu g* s`

`s=(25^2)/(2*0.80*9.8)`

`s=39.8 = 40 m`

Hence, The minimum distance is 40 m.