Answer:1.624 m
Step-by-step explanation:
Given
height of 2nd floor =5 m
time recorded is 0.58 sec
Let h be the height of third floor above 2 nd floor
![h=ut+(at^2)/(2)](https://img.qammunity.org/2020/formulas/physics/college/mkygvn7pueyiql0ysom5on2w5eob9dpp9n.png)
here u=0
t=time taken to cover height h
----------1
Now time taken to complete whole building length
----------2
Subtract 1 form 2
![5=(g(2t+0.58)(0.58))/(2)](https://img.qammunity.org/2020/formulas/physics/college/akrqwitso1kcuzwly9ltnu2u6na8cdgrac.png)
Taking gravity
![g=1 m/s^2](https://img.qammunity.org/2020/formulas/physics/college/9zl9j3zmyarvwtfephbdk02emu8h01p4lx.png)
1=(2t+0.58)(0.58)
t=0.57 s
Substitute the value of t in 1
h=1.624 m