28.3k views
3 votes
A boy in a sleigh glides on a 40 angle snow-covered hill. The coefficient of kinetic friction between the surface and the sled is 0.12. The acceleration of the sled is: a. 3.6 m / s^2

b. 0.76 m / s^2
c. 2.3 m / s^2
d. 5.4 m / s^2

1 Answer

3 votes

Answer:

option D

Step-by-step explanation:

given,

angle of the snow-covering hill (θ) = 40°

coefficient of kinetic friction = 0.12

acceleration of the shed = ?

we know,

F = m a...................(1)

now,


F = m g sin\theta -\mu_k N sin\theta.......(2)

comparing equation (1) with (2)


m a =m g sin\theta -\mu_k m g sin\theta


a = g sin \theta - \mu_k sin\theta


a = 9.8* sin 40^0 - 0.12* 9.8*  sin40^0

a = 5.54 m/s²

Hence, the correct answer is option D

User Siddharth Kumar
by
6.4k points