Question

On average, an eye blink lasts about 100 ms. How far does a fighter jet travel during a pilot's blink if the plane's average velocity is 3650 km/h?

Answer 1

Distance, d = 101.388 meters

Step-by-step explanation:

It is given that,

The average velocity of plane, v = 3650 km/h = 1013.88 m/s

The time for which eye blinks,
`t=100\ ms=0.1\ s`

Let d is the distance covered by the jet. It can be calculated as :

`d=v* t`

`d=1013.88\ m/s* 0.1\ s`

d = 101.388 meters

So, the distance covered by a fighter jet during a pilot's blink is 101.388 meters. Hence, this is the required solution.