Answer:
Distance, d = 101.388 meters
Step-by-step explanation:
It is given that,
The average velocity of plane, v = 3650 km/h = 1013.88 m/s
The time for which eye blinks,

Let d is the distance covered by the jet. It can be calculated as :

d = 101.388 meters
So, the distance covered by a fighter jet during a pilot's blink is 101.388 meters. Hence, this is the required solution.