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A jet lands on an aircraft carrier at 140 mi/h. What is its acceleration if it stops in 2.0 seconds?

1 Answer

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Answer:

Acceleration,
a=-31.29\ m/s^2

Step-by-step explanation:

It is given that,

Initial speed of the aircraft, u = 140 mi/h = 62.58 m/s

Finally, it stops, v = 0

Time taken, t = 2 s

Let a is the acceleration of the aircraft. We know that the rate of change of velocity is called acceleration of the object. It is given by :


a=(v-u)/(t)


a=(0-62.58)/(2)


a=-31.29\ m/s^2

So, the acceleration of the aircraft is
31.29\ m/s^2 and the car is decelerating. Hence, this is the required solution.

User Yvespeirsman
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