Question

A motorist drives north for 35.0 min at 85.0 km/h and then stops for 15.0 min. He then continues north, traveling 130 km in 2.00 h. (a) what is his total displacement? b) what is his average velocity?

Answer 1

(a) Total displacement will be 176.666 km

(b) Average velocity will be 62.3534 km/hr

Step-by-step explanation:

We have given a motorist drive for 35 minutes at 85 km/hr

We know that 1 hour = 60 minutes

So
`35\ minutes=(35)/(60)=0.5833hour`

So distance covered in 35 minutes = 0.5833×80 = 46.666 km

After he stops for 15 minutes that is 0.25 hour

Then he travel 130 km in 2 hour

(a) So total displacement = 130+46.666 = 176.666 km

(b) Total time t = 0.5833 +0.25 +2 = 2.8333 hour

Average velocity is given by
`average\ velocity=(total\ distance)/(total\ time)=(176.666)/(2.8333)=62.3534km/hr`