Question

The temperature of 1 m^3 of water is decreased by 10°C. If this thermal energy is used to lift the water vertically against gravity, what is the change in height of the center of mass?

Answer 1

h = 4271.43 m

Step-by-step explanation:

given,

Volume of the water = 1 m³

temperature decrease by = 10°C

heat removed from water

Q = m c ΔT

Q = ρ V c ΔT

= 1000 × 1 × 4186 × 10

= 4.186 × 10⁷ J

energy is used to do work to move the water against its weight

Q = force × displacement

4.186 × 10⁷ J = m g × h

4.186 × 10⁷ J = 1000 × 1 × 9.8 × h

h = 4271.43 m

hence, the change in height of is equal to h = 4271.43 m