Question

Two objects are dropped at the same time from heights of 0.49 m and 1.27 m. How long after the first object hits the ground does the second object hit the ground?

Answer 1

After 0.19288 sec second object hit the ground after hitting first object

Step-by-step explanation:

We have given two objects are dropped from at the same time from height 0.49 m and 1.27 m

As the object is dropped so its initial velocity will be zero u = 0 m/sec

For object 1 height h = 0.49 m

From second equation of motion

`h=ut+(1)/(2)gt^2`

`0.49=0* t+(1)/(2)* 9.8* t^2`

`t^2=0.1`

t = 0.31622 sec

For second object

`h=ut+(1)/(2)gt^2`

`1.27=0* t+(1)/(2)* 9.8* t^2`

`t^2=0.1`

t = 0.5091 sec

So difference in time = 0.5091-0.31622 = 0.19288 sec

So after 0.19288 sec second object hit the ground after hitting first object