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How long does it a take a runner, starting from rest to reach max speed, 30 f/s given acceleration 8 f/s^2? After finding the time, calculate the distance traveled in that time.

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Step-by-step explanation:

Given that,

Initial sped of the runner, u = 0

Final speed of the runner, v = 30 ft/s

Acceleration of the runner,
a=8\ ft/s^2

Let t is the time taken by the runner. It can be calculated using first equation of motion as :


t=(v-u)/(a)


t=(30-0)/(8)

t = 3.75 seconds

Let s is the distance covered by the runner. Using the second equation of motion as :


s=ut+(1)/(2)at^2


s=(1)/(2)* 8* (3.75)^2

s = 56.25 feet

Hence, this is the required solution.

User Amir Hosseinzadeh
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