Question

An observer is approaching at stationary source at 17.0 m/s. Assuming the speed of sound is 343 m/s, what is the frequency heard by the observer if the source emits a 2550-Hz sound?

Answer 1

the frequency heard by the observer is equal to 2677 Hz

Step-by-step explanation:

given,

velocity of the observer = 17 m/s

speed of the sound = 343 m/s

velocity of the source = 0 m/s

frequency emitted from the source = 2550 Hz

`f = f_0((v-v_0)/(v-v_s))`

`f = 2550* ((343+17)/(343-0))`

velocity of observer is negative as it is approaching the source. f = 2676.38 Hz ≈ 2677 Hz

hence, the frequency heard by the observer is equal to 2677 Hz