Question

A football is kicked from ground level at an angle of 38 degrees. It reaches a maximum height of 9.7 meters before returning to the ground. How long will the football spend in the air, in seconds?

Answer 1

Football will be in air for 2.8139 sec

Step-by-step explanation:

We have given maximum height h = 9.7 meters

Angle of projection
`\Theta =38^(\circ)`

We know that maximum height is given by
`h=(u^2sin^2\Theta )/(2g)`

So
`9.7=(u^2sin^(2)38^(\circ) )/(2* 9.8)`

`u^2=501.5842`

u = 22.396 m/sec

Time of flight is given by

`T=(2usin\Theta )/(g)=(2* 22.396* * sin38^(\circ))/(9.8)=2.8139sec`