Answer:
R = 668.19 ft
Step-by-step explanation:
given,
speed of the ball thrown by the pitcher = 100 mph
to travel maximum distance θ = 45°
distance traveled by the ball = ?
using formula
1 mph = 0.44704 m/s
100 mph = 44.704 m/s
![R = (u^2sin2\theta)/(g)](https://img.qammunity.org/2020/formulas/physics/college/6b0muutzbgc2a7eyur0mu6eu4k9lf6hgi0.png)
![R = (44.704^2sin2* 45)/(9.81)](https://img.qammunity.org/2020/formulas/physics/college/wlq1oqmcx806hik2jdxgdg0wcl4v9j341r.png)
R = 203.71 m
1 m = 3.28 ft
R = 203.71 × 3.28
R = 668.19 ft
hence, ball will go at a distance of 668.19 ft when pitcher throw it at 100 mph.