Question

In the return stroke of a typical lightning bolt, a current of 7.01×10^4 A (70.1 kA). exists for 20 μs. How much charge is transferred in this event ?

Answer 1

Charge, q = 1.402 C

Step-by-step explanation:

Given that,

Current from lightning bolt,
`I=7.01* 10^4\ A`

Time, t =
`t=20\ \mu s=2* 10^(-5)\ s`

Let q is the charge transferred in this event. We know that the total charge divided by time is called current. Mathematically, it is given by :

`I=(q)/(t)`

`q=I* t`

`q=7.01* 10^4* 2* 10^(-5)`

q = 1.402 C

So, 1.402 coulomb of charge is transferred in this event. Hence, this is the required solution.