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A coin is dropped from a height and reaches the ground in 2 seconds. Neglecting air resistance, from what height (in meters) was the coin dropped?

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Answer:

Coin is dropped from a height of 19.62 m

Step-by-step explanation:

We have given time t = 2 sec

As coin is drop means its initial velocity u = 0 m/sec

We have to find the height from which coin is dropped

From second equation of motion we know that


h=ut+(1)/(2)gt^2

So height
h=0*2+(1)/(2)* 9.81* 2^2=19.62m

So coin is dropped from a height of 19.62 m

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