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Write square root of 64 - square root of -289 as a complex number in the form of a+bi
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Write square root of 64 - square root of -289 as a complex number in the form of a+bi

User Tibbon
by
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2 Answers

6 votes

Answer:

8-17i

Explanation:

Got right on PLATO

User Latchmi
by
8.1k points
5 votes

Answer:


√(64)-√(-289)


=8-17i

Explanation:


√(64)=8 because 8(8)=64 and 8 is the positive square root of 64.


√(-289)=17i because 17i(17i)=289i^2=-289(-1)=-289.


√(64)-√(-289)


8-17i

User Yishus
by
7.9k points
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