Question

Enter your answer in the provided box. The balanced equation for the combustion of ethanol (ethyl alcohol) is: C2H5OH() + 3O2(g) → 2CO2(g) + 3H2O(g) How many g of CO2 will be produced by the combustion of 4 mol of ethanol? g CO2

Answer 1

Answer: The mass of carbon dioxide produced is 352 grams

Step-by-step explanation:

We are given:

Moles of ethanol = 4 mol

For the given chemical equation:

`C_2H_5OH(g)+3O_2(g)\rightarrow 2CO_2(g)+3H_2O(g)`

By Stoichiometry of the reaction:

1 mole of ethanol produces 2 moles of carbon dioxide

So, 4 moles of ethanol will produce =
`(2)/(1)* 4=8mol` of carbon dioxide

To calculate the mass of carbon dioxide, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

Moles of carbon dioxide = 8 moles

Molar mass of carbon dioxide = 44 g/mol

Putting values in above equation:

`8mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=(8mol* 44g/mol)=352g`

Hence, the mass of carbon dioxide produced is 352 grams