Calculate the number of mol of helium in a 2.01-L balloon at 29°C and 2.71 atm of pressure. Be sure to answer all parts. Imol

asked Jun 20, 2020 9.6k views

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by GuruM

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Answer:

0.220 mol He

Step-by-step explanation:

Hello,

Based on the ideal gas equation of state:

$PV=nRT\\n=(PV)/(RT) \\n=(2.71 atm * 2.01 L)/(0.082(atm*L)/(mol*K)*302K ) \\n=0.220 mol$

Best regards.

Majix answered Jun 26, 2020

by Majix

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