Question

Calculate the volume of 48.3 g of carbon monoxide at STP. Enter your answer in the box provided. L

Answer 1

Step-by-step explanation:

STP means standard temperature and pressure where values are as follows.

T = 273.15 K, P = 1 atm

According to ideal gas equation, PV = nRT. Since, it is given that mass is 48.3 g and we have to find the volume as follows.

n =
`\frac{mass}{\text{molar mass}}`

So, PV = nRT

V =
`\frac{mass}{\text{molar mass}} * (RT)/(P)`

=
`(48.3 g)/(28 g/mol) * (0.0821 L atm/mol K * 273.15 K)/(1 atm)` (molar mass of CO = 28 g/mol)

= 38.68 L

Thus, we can conclude that volume of 48.3 g of carbon monoxide at STP is 38.68 L.