Question

A sample of helium gas has a volume of 1.50 L at 159 K and 5.00 atm. When the gas is compressed to 0.200 L at 50.0 atm, the temperature increases markedly. What is the final temperature? Enter your answer in the provided box. K

Answer 1

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Step-by-step explanation:

The given data is as follows.

`V_(1)` = 1.50 L,
`T_(1)` = 159 K,

`P_(1)` = 5.00 atm,
`V_(2)` = 0.2 L,

`T_(2)` = ?,
`P_(2)` = 50.0 atm

And, according to ideal gas equation,

`(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))`

Hence, putting the given values into the above formula to calculate the value of final temperature as follows.

`(5.0 atm * 1.50 L)/(159 K) = (5 atm * 0.2 L)/(T_(2))`

`T_(2)` = 21.27 K

Thus, we can conclude that the final temperature is 21.27 K .