Question

The best player on a basketball team makes 95​% of all free throws. The​ second-best player makes 90​% of all free throws. The​ third-best player makes 80​% of all free throws. Based on their experimental​ probabilities, estimate the number of free throws each player will make in his or her next 40 attempts. Explain.

Answer 1

Answer: See explanation

Explanation:

The best player on a basketball team makes 95​% of all free throws. The number of free throws the best player will make in his or her next 40 attempts will be:

= 95% × 40

= 95/100 × 40

= 0.95 × 40

= 38

The​ second-best player makes 90​% of all free throws. The number of free throws the best player will make in his or her next 40 attempts will be:

= 90% × 40

= 90/100 × 40

= 0.90 × 40

= 36

The​ third-best player makes 80​% of all free throws. The number of free throws the best player will make in his or her next 40 attempts will be:

= 80% × 40

= 80/100 × 40

= 0.80 × 40

= 32