Question

Cyclopropane, C3H6, is used as a general anesthetic. If a sample of cyclopropane stored in a 2.36-L container at 10.0 atm and 25.0°C is transferred to a 7.79-L container at 5.56 atm, what is the resulting temperature? Enter your answer in the provided box

Answer 1

Step-by-step explanation:

The given data is as follows.

`V_(1)` = 2.36 L,
`T_(1)` =
`25^(o)C` = (25 + 273) K = 298 K,

`P_(1)` = 10.0 atm,
`V_(2)` = 7.79 L,

`T_(2)` = ?,
`P_(2)` = 5.56 atm

And, according to ideal gas equation,

`(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))`

Hence, putting the given values into the above formula to calculate the value of final temperature as follows.

`(10.0 atm * 2.36 L)/(298 K) = (5.56 atm * 7.79 L)/(T_(2))`

`T_(2)` =
`(43.3124)/(0.0792)` K

= 546.87 K

Thus, we can conclude that the final temperature is 546.87 K.