Answer:
![F_A =5.625*10^1^6N](https://img.qammunity.org/2022/formulas/physics/high-school/m7nj9hhrgwdbdn67z3auit307b8i2z2xjg.png)
Step-by-step explanation:
From the question we are told that
50,000 years ago,
A giant 4.5 107-kg meteor
180-m-deep hole
20,000 m/s
Generally for this problem the energy change is given as
![\triangle E=(1)/(2) mv^2 +mgd](https://img.qammunity.org/2022/formulas/physics/high-school/uiyz2wi55cx6v23awdhgne1el1ftw8ne7t.png)
Having the potential and kinetic energy in place
Mathematically solving for Average force
![F_A](https://img.qammunity.org/2022/formulas/physics/high-school/zvxieunfg11qe8a5eo45eo0fe11rhazgiv.png)
![\triangle E=F_a*d](https://img.qammunity.org/2022/formulas/physics/high-school/5nw5vwz13f38p7yp61l9oz0o9104v28bow.png)
![F_A =(1/2* 4.5*10^7(20,000)^2-kg+4.5*10^7*9.81*160)/(160)](https://img.qammunity.org/2022/formulas/physics/high-school/6f0ai3u7yghacfe23dx291x8yqiy93b0kh.png)
Therefore Average force
is given by
![F_A =5.625*10^1^6N](https://img.qammunity.org/2022/formulas/physics/high-school/m7nj9hhrgwdbdn67z3auit307b8i2z2xjg.png)