Question

In the laboratory you are asked to make a 0.575 m nickel(II) acetate solution using 19.9 grams of nickel(II) acetate.

Answer 1

Answer: The volume of solution is 195.8 mL

Step-by-step explanation:

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

`\text{Molarity of the solution}=\frac{\text{Mass of solute}* 1000}{\text{Molar mass of solute}* \text{Volume of solution (in mL)}}`

We are given:

Molarity of solution = 0.575 M

Given mass of nickel (II) acetate = 19.9 g

Molar mass of nickel (II) acetate = 176.8 g/mol

Putting values in above equation, we get:

`0.575M=\frac{19.9g* 1000}{176.8g/mol* \text{Volume of solution}}\\\\\text{Volume of solution}=(19.9* 1000)/(176.8* 0.575)=195.8mL`

To prepare 0.575 molar nickel (II) acetate solution, we need to add 19.9 grams of nickel (II) acetate to 195.8 mL of solution.

Hence, the volume of solution is 195.8 mL