Question

According to the following reaction, how many grams of chloric acid (HClO3) are produced in the complete reaction of 31.6 grams of chlorine gas? 3 C12(g) + 3 H2O(1) ► 5 HCl(aq) + HCO3(aq) grams HC103

Answer 1

`m_(HClO_3)=12.7gHClO_3`

Step-by-step explanation:

Hello,

Considering the reaction:

`3Cl_2(g)+3H_2O(l)-->5HCl+HClO_3`

The molar masses of chlorine and chloric acid are:

`M_(Cl_2)=35.45*2=70.9g/mol\\M_(HClO_3)=1+35.45+16*3=84.45g/mol`

Now, we develop the stoichiometric relationship to find the mass of chloric acid, considering the molar ratio 3:1 between chlorine and chloric acid, as follows:

`m_(HClO_3)=31.6gCl_2*(1molCl_2)/(70.9gCl_2) *(1molHClO_3)/(3mol Cl_2) *(85.45g HClO_3)/(1mol HClO_3) \\m_(HClO_3)=12.7gHClO_3`

Best regards.