Question

The weight of a liter of oil that has a specific gravity 0.83 is a) 3.0 N b) 8.1 N c)0.18N d) 18.0 N e) None of these

Answer 1

Weight of oil will be 8.1 N

So option (b) is correct

Step-by-step explanation:

We have given specific gravity of oil = 0.83

We know that specific gravity is given by
`specific\ grviy=(density\ of\ oil)/(density\ of\ water)`

So
`0.83=(density\ of\ oil)/(1000)`

Density of oil
`83kg/m^3`

Volume is given as 1 liter =
`10^(-3)m^3`

We know that mass
`m=volume* density=10^(-3)* 83=0.83`

Weight of oil is given by
`W=mg=0.83* 9.81=8.1N`

So option (b) is correct