Question

A fluid has a viscosity of 13 P and a specific gravity of 0.94. Determine the kinematic viscosity of this fluid in units of ft²/s. Round the result to 4 decimal places.

Answer 1

kinematic viscosity is 0.0149 ft²/s

Step-by-step explanation:

given data

specific gravity S = 0.94

density ρ = 0.94 × 1000

viscosity μ = 13 Poise = 1.3 Pa-sec

we know 1 poise = 0.1 pas

to find out

kinematic viscosity

solution

we will apply here Kinematic viscosity formula that is

kinematic viscosity =
`(\mu)/(\rho)` ..................1

put here value in equation 1

and here ρ is density and μ is viscosity

kinematic viscosity =
`(1.3)/(0.94*1000)`

kinematic viscosity = 1.382978 ×
`10^(-3)` m³/s

so kinematic viscosity is 0.0149 ft²/s