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What are the coordinates of the hole in the graph of the function?

What are the coordinates of the hole in the graph of the function?-example-1
User Rasheedah
by
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1 Answer

3 votes

Answer:

The answer to your question is: (5/2, -6)

Explanation:

Given f(x) = (6x - 36) / (2x² - 17x + 30)

Factorize both, numerator and denominator

Numerator = 6(x - 6)

Denominator = 2x² - 12x - 5x + 30

= 2x(x - 6) - 5(x - 6)

= (x - 6) (2x - 5)

Now f(x) = 6(x - 6) / (x - 6) (2x - 5) Cancel (x - 6)

f(x) = 6 / 2x - 5

Find the hole 2x - 5 = 0

2x = 5

x = 5/2

In 5/2 there is a hole, in y is approximately -6

User Hamed Tabatabaei
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