Answer:
70°
Explanation:
If in the quadrilateral ABCD diagonal BD is an angle bisector for angles B and D, then
Consider triangles ABD and CBD. In these triangles,
- ∠ABD ≅ ∠DBC;
- ∠ADB ≅ ∠BDC;
- BD ≅ BD.
Hence, triangles ABD and CBD are congruent by ASA postulate.
So, AD ≅ DC.
Now, consider triangle ADC. This is an isosceles triangle, because AD ≅ DC. In this triangle, m∠ADC = m∠ADB + m∠BDC = 20° + 20° = 40°. AC is the base. Angles DAC and DCA are congruent as adjacent angles to the base AC, so
m∠DAC = 1/2 (180° - 40°) = 70°