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What is the density of an alloy formed by 10 cm^3 of copper (density = 8.9g / cm^3) and 10 cm^3 of silver (density= 10.5 g / cm^3)?

User Cameron S
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1 Answer

4 votes

Answer:

9.7g / cm^3

Step-by-step explanation:

To calculate a conbined density we must find the ratio between the sum of the masses and the sum of the volumes remembering that the equation to find the density is α=m/v, taking into account the above the following equation is inferred.

αc=copper density

αs=silver density

Vs=volume of silver

Vc=volume of copper

α= density of alloy


\alpha =\frac{({\alpha c}{Vc} +{\alpha s }{Vs} )}{Vs+Vc} \\\alpha =((8.9)(10) +(10.5)(10) )/(10+10) \\\\\alpha =9.7g / cm^3

the density of the alloy is 9.7g / cm^3

User AndraD
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