Question

a 0.125kg salt shaker sits 0.146m from the center of rotating lazy susan. if it moves 1.23m/s without sliding off what is its centripetal acceleration?(unit=m/s^2)

Answer 1

Step-by-step explanation:

the top of me is correct i took notes on physics a lot of notes so i have all of the notes written down so the top of me is right! :) its 10.4 m/s

Answer 2

`10.4 m/s^2`

Step-by-step explanation:

For an object moving in uniform circular motion, the centripetal acceleration is given by:

`a=(v^2)/(r)`

where

v is the tangential speed

r is the radius of the circle

In this problem, we have:

r = 0.146 m is the radius of the circle

v = 1.23 m/s is the tangential speed

Substituting the numbers, we find:

`a=(1.23^2)/(0.146)=10.4 m/s^2`