Question

Assume your computer clock runs at the speed of 2.5 GHz (G=10^9).

a. what is the clock cycle time of your computer? Reduce your answer to the final value in microseconds.

b. what is the number of clock cycles in one milisecond?

c. if the the execution time of a program on average is 100 X 10^-3 millisceonds, how many programs can the computer execute in one second?

Answer 1

a)
`T=4*10^(-4)μs`

b)
`N=2.5*10^6 cycles`

c) 10000 programs.

Step-by-step explanation:

a) We know that the frequency is the inverse of the period, so:

`f=(1)/(T)\\\\T=(1)/(f)\\T=4*10^(-10)s`

1μs is equal to
`1*10^(-6)s`

so
`T=4*10^(-4)us`

b) If in a second there are 2.5*10^9 cycles:

`N=2.5*10^9*(1*10^(-3))=2.5*10^6 cycles`

c) we have to make a conversion, we know that a program takes 100*10^(-3) milliseconds, that is, 1*10^(-4) seconds so in 1 second we can execute:

`P=(1s)/(1*10^(-4)s)=10000`

10000 programs.